Welcome to Mrs. Young's calculus class blog! Each week, I will start a new post. Students, you can write questions for me or chat with each other about how to solve a particular problem. As part of your class participation grade each week, every student must comment at least once to my post or another student's comment. I look forward to spending this year with you. Enjoy!
Sunday, February 19, 2012
Week 8
This week is pretty short because we don't have school on Monday and Friday we won't have class because of the school carnival. We are going to start chapter 7 this week, which is our last chapter of new material! The first part of section 7.1 is a review of some things we've already talked about regarding position, velocity, and acceleration. Section 1 is called "Integral as Net Change." In your own words, I'd like you to describe what that phrase means: "an integral as net change." We talked about this when we were learning about area under the curve.
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The phrase means that the integral give the final number, so the positive are or distance. So when you integrate you receive the answer without the negative portions.
ReplyDeleteNot quite Christian. The value of an integral can be negative. There can be negative displacement. I'd like you to try and re-think your answer and then respond again. Thank you.
ReplyDeleteThe value of an integral gives you the net area or the displacement. When you solve an integral over a certain period, the answer will give you the net change or the change in position of the particle.
ReplyDeleteWhen you solve for an integral the answer is the net area. so when you evaluate an integral on a certain interval you will get the net change of the position of the particle.
ReplyDeleteOk, but what does net change mean Nate?
ReplyDeleteThe value of an integral of a function is the net area or displacement of that function. If you take the integral of a function with a specified interval, you will get the net change or the change in position of that particle.
ReplyDeleteThe value of an integral of a rate change gives you net change. We can get net area or displacement. It basically the antiderivative of function.
ReplyDeleteThe phrase means that the integral will give the positive and negative displacements for an object. Therefore if you are trying to find the change in position you must find the net change of position because an object does not always go to positive directions
ReplyDeleteMost of you are dancing around my question. We know that an integral gives you net change. You're basically just re-stating my question. I want to know that you understand what "net change" is. Please try to explain what net change is, not just tell me that an integral gives you net change.
ReplyDeleteI think the net change is the disPlacement of a equation. It's showed in term of the area under or above the graph with the axises.
ReplyDelete